tentukab konsentrasi ion [H+] dan ion [OH-] dalam larutan CH3 COOH 0,1 m dengan ka CH3 COOH=10-5
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Jawaban:
[H+]= 10^(-3)
[OH-]= 10^(-11)
Penjelasan:
[tex] {h}^{ + } = \sqrt{ka \times ma} \\ = \sqrt{ {10}^{ - 5} \times 0.1} \\ = \sqrt{ {10}^{ - 6} } \\ = {10}^{ - 3} [/tex]
pH + pOH= 14
-log(H+) + -log (OH-)= 14
log(H+ × OH-)= -14
H+ × OH-= 10^(-14)
[tex] {10}^{ - 3} \times {oh}^{ - } = {10}^{ - 14} \\ {oh}^{ -} = {10}^{ - 11} [/tex]
[answer.2.content]
